Question

Simplify: x^2 - 3x- 18/ x^2 - 2x - 24 divided by 1/x+4

Answer 1

do you mean
\[ \LARGE{ \frac{\frac{x^2-3x-18}{x^2-2x-24}}{\frac{1}{x+4}}} \]

Answer 2

yes

Answer 3

OK
do you know how to write into factors like this
\[ x^2-3x-18=(x-\quad)(x+\quad) \]

Answer 4

x-6 and x+3

Answer 5

that is very good!
do the same for x^2 - 2x - 24
what do you get?

Answer 6

x+4 and x-6

Answer 7

that is great. so we have this far
\[ \LARGE \frac{\frac{x^2 - 3x- 18}{x^2 - 2x - 24}}{\frac{1}{x+4}}=
\frac{x^2 - 3x- 18}{x^2 - 2x - 24}\cdot\frac{1}{x+4}=
\frac{(x-6)(x+3)}{(x+4)(x-6)}\cdot\frac{x+4}{1} \]

can you go forward?

Answer 8

sorry in the middle it is
\[ \LARGE \frac{x^2−3x−18}{x^2−2x−24}\cdot\frac{x+4}{1} \]

Answer 9

and on the far right (it seems you might not see it)
\[ \LARGE \frac{(x-6)(x+3)}{(x+4)(x-6)}\cdot\frac{x+4}{1} \]

Answer 10

what do you get once you simplify?

Answer 11

i'll be right back.
you should be able to do it.
it is easy!

Answer 12

so what did you get?