Given: sec theta= -8/3, tan theta is positive.
1. In what quadrant is the theta located?

Question

Given: sec theta= -8/3, tan theta is positive.
1. In what quadrant is the theta located?

anonymous · Answer

sec=1/cos
cos is negative in Q2,Q3
tan is positive in Q1,Q3
Therefore Q3

anonymous · Answer

medal please

anonymous · Answer

Can you help me with a few more like this?

anonymous · Answer

Thanks man

anonymous · Answer

okay
I want to feel good about myself

anonymous · Answer

Do you mind if i upload the picture of the 6 problems i need answers to?

anonymous · Answer

yeah sure

anonymous · Answer

attachment

anonymous · Answer

-8/17    8/15    -15/17   -17/18   15/8 
starting from 47

anonymous · Answer

is the last one -15/8 cause i dont have 15/8

anonymous · Answer

one sec

anonymous · Answer

OH man I thought that the information given was from the problem you gave on this website.
I need a minute dude I need to redo all of them!!!!

anonymous · Answer

The picture i uploaded is different from the first one.

anonymous · Answer

Oh, and im not a dude.

matheducatormcg · Answer

$$\csc \left( \theta \right)=-17/15$$
means $$\sin \left(\theta\right)=-15/17$$
but problem said $$\cos (\theta)$$ was positive, which occurs in the 1st and 4th quadrant.
Therefore, 15 is your opposite measurement, 17 is your hypotenuse measurement.  The adjacent measurement is given by Pythagorean theorem, $$\sqrt{17^{2}-15^{2}}$$ 
Use this measurement and right triangle trig to find other ratios.

matheducatormcg · Answer

oh, I forgot to mention that $$\sin (\theta)=-15/17$$
but $$\cos (\theta)$$ is positive,
therefore you are in the 4th quadrant.

anonymous · Answer

which ones are you working on? the picture above?