Question

1/(x^2-7x+10) = x/(x-5) + 1(x-2)

Answer 1

whats the question..?

Answer 2

Solve for x

Answer 3

ok... the left hand side in factorised form is

\[\frac{1}{(x -2)(x -5)} \]

the write hand side needs a common denominator

\[(x -2)(x-5)\]

you can rewrite the right hand side as

\[\frac{x}{(x -5)} + \frac{1}{(x -2)} = \frac{x (x -2) + (x -5)}{(x-2)(x-5)}\]

since both sides now have the same denominator then equate he numerators

1 = x(x-2) + x - 5

simplifying

\[1 = x^2 - 2x + x - 5 \]

or \[x^2 - x - 6 = 0\]

you can solve this equation by factorising

hope this helps

Answer 4

Oh , lol well thank you .. it did !

Answer 5

well done