Question

What is the exact value of 8 times q squared all over the square root of q to the seventeenth power.? Simplify if possible.
Answer

8 the square root of q all over q to the sixth power.

8 the square root of q all over q to the seventh power.

8 the square root of q all over q to the fifth power.

8 the square root of q all over q to the fourth power.

Answer 1

is this the question

\[\frac{8q^2}{\sqrt{q^{17}}}\]

Answer 2

yup

Answer 3

ok looking at the denominator

\[\sqrt{q^{17}} = \sqrt{q^{16} \times q} = \sqrt{q^{16}} \times \sqrt{q} = q^8 \]

so the fraction is now

\[\frac{8q^2}{q^8\sqrt{q}}\]

you now need to eliminate a common factor to gte your answer

Answer 4

the fraction can be written as

\[\frac{ 8 \times q \times \sqrt{q} \times \sqrt{q}}{q^8\sqrt{q}}\]

eliminate common factors

Answer 5

we eliminate sqrt(q)

Answer 6

yes but there is still a common factor to eliminate

\[\frac{8\times q \times \sqrt{q}}{q^7\times q}\]

Answer 7

oh yea q and q

Answer 8

I think you now have the answer

Answer 9

is it
is it with a sixth power or seventh power.

Answer 10

well you will have the 7th power in the denominator

Answer 11

ok thanks