Question

Find the equation of a circle that has its center at (6, -4) and has a radius of 3.


(x+ 6)2+ (y- 4)2= 9
(x- 6)2+ (y- 4)2= 9
(x+ 6)2+ (y+ 4)2= 9
(x- 6)2+ (y+ 4)2= 9

Answer 1

hmm so what do you think is the answer here?

Answer 2

I think it is the first one

Answer 3

why do you think so?

Answer 4

because the center is (6,-4) and in the first equation (x+ 6)2+ (y- 4)2= 9

Answer 5

but the equation of a circle is \[(x-h)^2 + (y-k)^2 = r^2\]
right?

Answer 6

h is the x-coordinate of the center
k is the y-coordinate of the center

Answer 7

hold on i am going to use the equation quick

Answer 8

sure :)

Answer 9

I am not sure if I did it correct still but, i actually got the last one

Answer 10

ahh that's right! congrats

Answer 11

thank you:D

Answer 12

<tips aht>

Answer 13

hat*