Find the period of the minute hand of a wall clock. Find the angular frequency of the minute hand of a wall clock. Find the frequency of the minute hand of a wall clock.

Question

anonymous · Answer

i can tell you that the period is 3600s, if you can also explain this i would be greatful

ganpat · Answer

1. Period = 60 min * 60 = 3600 Sec

2. Angular velocity = (2 * Pi * N ) 60.. = ( 2 * pi * 360) / 60 =  37.699 .

3. Frequency  = 1/N =  1/ 360 ...

I guess, i am right...

@Vaidehi09 : what say ? u good at Physics..

anonymous · Answer

it says that they are incorrect. thanks for trying.

ganpat · Answer

lol, m sorry !!!

anonymous · Answer

Period T is right. 
but angular velocity w = 2 pi /T = 2pi/3600 = 91/1800 rad/sec
and frequency = 1/T = 1/3600

anonymous · Answer

it says angular velocity is 1.75*10^-3. is your answer in rad/s?

ganpat · Answer

yes ..

anonymous · Answer

the frequency was 1/3600 thank you for that.

anonymous · Answer

can anyone explain angular velocity please? and thanks for the effort ganpat

anonymous · Answer

hey wait.....there was a typing error....w = pi/1800 rad/s

anonymous · Answer

aww bummer, too bad i only had one try left on that question. thanks though now that i understand it better

anonymous · Answer

glad to help :) just remember the formulae and it'll be a piece of cake!