Question

can someone give me some *possible to solve* integrals? i'd like to practice :)

Answer 1

and please no mimintegrals or omnintegrals :p

Answer 2

\[\int\limits \sqrt{a^{2}-x^{2}}dx\]
i suppose u can do that!!

Answer 3

Here's a fun one: \[\int\limits\frac{1}{\ln(x+1)} dx\]
Or:
\[\int\limits\sqrt{tanx} dx\] (without partial fracrtions)

Answer 4

\[\int\limits_{1}^{2}\ln x/x ^{2}\]

Answer 5

No mimintegrals? :(

Answer 6

i said no mimintegrals or omnintegrals @Mimi_x3 :p

Answer 7

I feel discrimininated :P

Answer 8

I shall insert a complaint for the discrimination :P

Answer 9

\[\int \frac{\ln x}{x^2}dx\]
u = lnx
du = 1/x dx

dv = 1/x^2 dx
v = -2/x^3 dx

\[\frac{-2\ln x}{x^3} - \int -\frac{2}{x^4}dx\]
it's integrable now

Answer 10

\[\int \sqrt{a^2 - x^2} dx \implies \sin (\frac{x}{a})\]
right?

Answer 11

i mean \[\sin^{-1} (\frac{x}{a})\]

Answer 12

nope!!

Answer 13

My integral is left isolated..

Answer 14

\[\int \frac{1}{\ln (x+1)}dx\]
let u = x +1
du = dx
\[\int \frac{du}{\ln u}\]
you do the rest :p

Answer 15

Wrong!

Answer 16

heh :p

Answer 17

Not thateasy (:

Answer 18

that's why i left it haha

Answer 19

However, the second one \[\int\limits\sqrt{tanx} dx\] without partial fractions is doable! (:

Answer 20

lol :p

Answer 21

Atleast try! you wanted practice.

Answer 22

tell me how to get the integral of sin^4 x dx then ill give you that integral in a heartbeat :p

Answer 23

Reduction formulae..

Answer 24

http://en.wikipedia.org/wiki/Integration_by_reduction_formulae

I gotta review these lol

Answer 25

is there no one else?

Answer 26

\[\large\int\limits (x^{3m}+x^{2m}+x^m) (2x^{2m}+3x^m+6)^{1/m} dx\]

Answer 27

uhhh nevermind im closing this now :S lol

Answer 28

you guys have already proven you are capable of giving hard ones :P lol

Answer 29

that is a nice one
let u=x^m

Answer 30

@mukushla .....is is an awsome one!!!!!

Answer 31

@lgbasallote
\[(\sin^{2}x+\cos^{2}x)^{2}=1\]

i think this is the starting for ur problm