When do you "plug in and simplify" to find a limit?
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OpenStudy (lgbasallote):
when the limit exists?
OpenStudy (anonymous):
hmm
OpenStudy (lgbasallote):
would you like an example?
OpenStudy (anonymous):
yes please
OpenStudy (lgbasallote):
\[\huge \lim_{x \rightarrow 1} \quad \frac{x^2 - 1}{x-1}\]
try plugging in 1 into x
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OpenStudy (anonymous):
undefined
OpenStudy (anonymous):
could it be when the function us continuis?
OpenStudy (anonymous):
continuous
OpenStudy (lgbasallote):
could it be what?
OpenStudy (anonymous):
when the function is continuous
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OpenStudy (lgbasallote):
yeah...could be what?
OpenStudy (lgbasallote):
you said could "it" be when the function is continuous
what is that "it"?
OpenStudy (lgbasallote):
im going to explain my point...
in the example i gave when you plug in immediately you will get undefined
but if you simplify it first
\[\lim_{x\rightarrow 1} \quad \frac{(x+1)\cancel{(x-1)}}{\cancel{(x-1)}}\]
so therefore you can get \[\lim_{x\rightarrow} x+ 1 \implies 1 + 1 \implies 2\]
do you get that?
OpenStudy (anonymous):
yes
OpenStudy (lgbasallote):
great :)
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OpenStudy (anonymous):
so you can plug in and simplify when the function is continuos?
OpenStudy (lgbasallote):
when the function is continuous yes :)
but in this case it is not continuous so you have to simplify first