Question

If x is a positive number, what is the least value of x^2-2x+3?

Answer 1

fo minima,double derivative of function wrt to x is negative

Answer 2

sorry positive

Answer 3

what will be the value then?

Answer 4

2x-2=0
2x=2
x=1

for minima,
f(1)=1-2+3
=4-2
=2
in this question,i am assuming f(x)=x^2-2x+3

Answer 5

But the answer isn't 2

Answer 6

least value is 1

Answer 7

No it is't 1 either...

Answer 8

no sorry
i am confused wait

Answer 9

find the first derivative , make it equal to zero
u will get x=1
then find the second derivative by putting the value of x=1 in it
if value of second derivative is positive then we will say that the given function has a minimum value at x=1
to find least value put x=1 in original equation
u will get the answer as 2

Answer 10

is it 3 ?

Answer 11

Nup

Answer 12

2 has to be the answer

Answer 13

this Q from calculus, or quadratic equations ?

Answer 14

Quadratic eq

Answer 15

The answer given is 0 ?

Answer 16

x coordinate of vertex = -b/2a = 2/2 = 1

so, x is a positive number.

y coordinate of vertex is the minimum value. can u find that ?

Answer 17

you mean 0 is the wrong answer, it should be 2?

Answer 18

@nitz is right i am also getting 2..

ur book is wrong... yeah :)

Answer 19

okey... thnx

Answer 20

np :)

Answer 21

the final answer is 2