Find the two numbers whose sum is 8, if the product of one number and the cube of the other is a maximum value?
this is calculus.. .?
yup yet is the answer is 2,6
HOW?
@matricked: u r right, can u please explain me..?
if one number is x then u have to maximise x^3(8-x) on simply differentiating u get the values either 0 or 6 and then test for max condition using second order
What is meant by maximum value here?
it means max value of x^3(8-x)
Okey, how will we maximise x^3(8-x)? By equating it to what?
if u equate it to something then u willsolve for such particular values of x satisfying ur choice u need to differentiate x^3(8-x) and obtain 24x2-4x3and equate it to0 to obtain the values of x(extremums) as x=0,6
i m not getting it...
if u equate 24x2-4x3=0 thn the values of x is 0 or 6....
24x2-4x3=0 or 24x^2-4x^3=0 ?
24x^2-4x^3=0 ?
where are the powers in 24x2-4x3=0
generally its understood...
if we multiply 3x^2(8-x) then we'll get 24x^2-3x^3..
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