Question

\[ t = \frac{1}{2}
sin^{-1}
\left(\frac{x-1}{\sqrt{2}}\right)
-\frac{\pi}{8}\]
solve for \(x\)

Answer 1

\[x=1+\sqrt{2} \sin (2t+\frac{\pi}{4})\]
am i right?

Answer 2

I don't know lol..
I can't remember how to do these

Answer 3

\[x=1+\sqrt{2} \sin (2t+\frac{\pi}{8})\]??

Answer 4

don't know; i have to sketch it

Answer 5

\[t=\frac{1}{2}\sin^{−1}(\frac{x−1}{\sqrt{2}})−\frac{π}{8}\\ \sin^{−1}(\frac{x−1}{\sqrt{2}})=2t+\frac{\pi}{4}\]

Answer 6

ok till there?

Answer 7

I got it. Thanks!

Answer 8

ok