Ellipses- Given the Vertices and the Foci how can one find the equation of the ellipse? Please give an example.
Write an equation for the ellipse having one focus at (0, 3), a vertex at (0, 4), and its center at (0, 0). Since the focus and vertex are above and below each other, rather than side by side, I know that this ellipse must be taller than it is wide. \[a^2\] will go with the y part of the equation. Also, since the focus is 3 units above the center, then c = 3; since the vertex is 4 units above, then \[a=4 \] The equation \[b^2 = a^2 – c^2 \] gives me\[ 16 – 9 = 7 = b^2 \]. (Since I wasn't asked for the length of the minor axis or the location of the co-vertices, I don't need the value of b itself.) \[\frac { y^{ 2 } }{ 16 } +\frac { { x }^{ 2 } }{ 7 } =1 \]
@TrigSucksDaww Is there any need to explain further
Yes, Vertices (+-9,0) Foci (+-6*Sqrt(2),0)
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