Mathematics
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OpenStudy (hesan):
If a β are not real cube roots of unity, then a^5+ β^5+a β =? (a refers to alpha)
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OpenStudy (anonymous):
Put:
\[\alpha = w\]
\[\beta = w^2\]
OpenStudy (hesan):
what's the answer?
OpenStudy (anonymous):
You tell me..
OpenStudy (hesan):
i don't know...
OpenStudy (hesan):
What 'll be the answer after putting α=w
β=w2
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OpenStudy (anonymous):
What you don't know tell me..
OpenStudy (hesan):
I dont know the answer of this question.. please tell me if u've solved this?
OpenStudy (anonymous):
Firstly put and then show me your work...
do this much only..
OpenStudy (hesan):
ok, wait...
OpenStudy (hesan):
I'm getting the answer 0
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OpenStudy (anonymous):
You are right if you are getting zero..
OpenStudy (hesan):
If a β are not real cube roots of unity, then we always put α=w and β=w^2?
OpenStudy (anonymous):
Yes..
OpenStudy (anonymous):
You can put also b=w and a = w^2
That does not matter..
OpenStudy (hesan):
okey then what will be the value of (α^4+β^4) + 1/αβ
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OpenStudy (anonymous):
You tell me..
OpenStudy (hesan):
i m getting w+w ?
OpenStudy (anonymous):
You are wrong..
it is again zero..
OpenStudy (hesan):
oh yes, i forgot to include 1. yup its zero
OpenStudy (anonymous):
yes it is..
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OpenStudy (hesan):
the shortest trick is to put α and β w and w^2 respectively... Thanks!
OpenStudy (anonymous):
FORMULAS TO REMEMBER IN THIS:
\[\huge \color{green}{1 + \omega + \omega^2 = 0}\]
\[\huge \color{blue} {\omega^3 = 1}\]