A stuntwoman (m=60kg) jumps off the roof of a building, and then safely lands on a pile of cardboard boxes, which takes 0.4s to crumple and bring her to a complete stop. The force of the cardboard boxes on the stuntwoman is 2000N and the area of the force vs. time graph that was provided to me was 600 N/s.

What was the stuntwoman's momentum and velocity at t=0 seconds (just prior to hitting the boxes)?
HELP ME

Question

A stuntwoman (m=60kg) jumps off the roof of a building, and then safely lands on a pile of cardboard boxes, which takes 0.4s to crumple and bring her to a complete stop. The force of the cardboard boxes on the stuntwoman is 2000N and the area of the force vs. time graph that was provided to me was 600 N/s. 

What was the stuntwoman's momentum and velocity at t=0 seconds (just prior to hitting the boxes)?
HELP ME

ujjwal · Answer

$$Force=\frac{\Delta P}{\Delta t}$$where $\Delta P$= change in momentum
$\Delta t$  is time of impact

Let P be initial momentum. Since the body finally comes to rest. change in momentum=P
so, here, 
2000 = P/0.4
or, P=800

Also, P=mv
therefore, v=P/m=800/60=13.33 m/s

anonymous · Answer

thx :)