Question

Find an equation of the tangent line to the curve at the given point.
y = 3/sin x + cos x, P = (0, 3)

Answer 1

do u know what will be the slope of tangent line?

Answer 2

I know that you have to differentiate the equation, then using x solve it which will result in the slope but I keep getting the wrong answer

Answer 3

oh wait

Answer 4

x=0 is not in the Domain of y = 3/sin x + cos x !!!

Answer 5

so does that mean that the answer is 0?

Answer 6

or would it be y=-3x-3

Answer 7

that mens y = 3/sin x + cos x is not continuous at all in x=0 and u cant find a tangent line

Answer 8

or maybe im wrong
@waterineyes

Answer 9

the answer was -3x+3 I must've done the math wrong and made a mistake

Answer 10

I have no clue about this... @mukushla
Sorry..
dpalnc will clear all the doubts..

Answer 11

is this your function: \(\large y=\frac{3}{sinx + cosx} \)

Answer 12

if no, then @mukushla is correct... x=0 is not in the domain..

Answer 13

yes it was but I submitted that one and made a silly algebraic mistake. can you help me with another one:

Find an equation of the tangent line to the given curve at the specified point.
5x/x+2 at point 3,3

Answer 14

the procedure is the same as the previous one... you'll need to find the derivative...

Answer 15

just don't make the same algebraic mistake....

Answer 16

show us what you've done and we can see where your error might be....

Answer 17

at least tell us what you have for the derivative...

Answer 18

i have the slope as 7/25 when I found the derivative but I'm not sure if thats right

Answer 19

at x=3 your slope is not correct... what do you have for the derivative?

Answer 20

-5x/(x+2)^2

Answer 21

i got something else for the derivative... the denominator is correct though...

Answer 22

wanna work out the derivative with me?

Answer 23

is there a -5x in it?

Answer 24

in the numerator*

Answer 25

when simplified, no, the numerator should be some constant.

Answer 26

i set it up as:

x+2 (d/dx) 5x - 5x (d/dx) x+2

Answer 27

the derivative of 5x is 1and so is the derivative of x+2 so its x + 2 -5x

Answer 28

derivative of 5x is 5

Answer 29

ok... this is just the numerator....
\(\large (x+2)[5x]'-(5x)[x+2]' \)
\(\large =(x+2)\cdot 5-(5x)\cdot 1 \)
\(\large =5x+10-5x \)
\(\large =10\)

Answer 30

thank you so much now I understand

Answer 31

so you have the slope of the tangent line at x=3?

Answer 32

2/5

Answer 33

yes... and use that along with the point (3, 3) to find point-slope form for the equation of the tangent line... :)

Answer 34

2/5x+9/5

Answer 35

can you help me with another one:

Answer 36

sure.. close shop on this question and post up another.... this one is making me dizzy going up and down....:|