Question

3010 J / 0.06338 mol NaOH = 4.75X10^4 J/mole X 1 kJ/1000 J = 47.5 kJ/mol NaOH
Write the balanced chemical reaction and enthalpy change? I am not just looking for the answer, in fact just the explanation on how to do it would be great(:
H2O + NaOH → Buffer solution
44kJ/mole of sodium hydroxide dissolved
44kJ/mole energy used
Enthalpy change: 47.5 kJ/mol NaOH

Answer 1

I'm a little confussed by the question it seems that something is left out. Maybe an unbalanced equation? Or the Rxn Equation in word form?

Answer 2

Yea sorry I wasn't sure if I put enough info! Here is everything I have..
H2O + NaOH → Buffer solution
44kJ/mole of sodium hydroxide dissolved
44kJ/mole energy used
Enthalpy change: 47.5 kJ/mol NaOH

Answer 3

No reaction occurs

Answer 4

The NaOH dissolves into its ion form; they are hydrated by water, but they do not react with water.

Answer 5

So then there would be no equation?

Answer 6

There will be "no reaction" between NaOH and H2O.

Answer 7

Okay sorry about the confusion. Thanks!(:

Answer 8

Do you think you can help me with another question? Sorry if I am pushing my luck...

Answer 9

I'll try.

Answer 10

HCl Solution 101mL
NaOH Solution 101mL
Initial HCl Solution 25.2oC
Mixed Solution Temperature 28.2oC
Determine the number of moles of NaOH?

Answer 11

What is the topic?

Answer 12

And what is "oC"?

Answer 13

oC is degrees Celsius..This is part of a lab I am doing b/c I am taking an online course but its really bad at explaining things..it was on the topic of Caliometry and enthalpy change in a reaction.