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For all x and Y in Q: if x
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i would say this is true but i bet i am wrong lol
ull find some fraction that will make it false somehow
right
Its correct???? YAYYYYYYY
yes
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Awesome :D
If you want to prove it, you would select two reduced fractions \(x=a/b\) and \(y=c/d\) such that \(x<y\). Then, look at the numbers \[\frac{ad}{bd}\]\[\frac{bc}{bd}\]We know that \(ad<bc\) and they are integers by our assumption. If \(bc\neq ad+1\) then \[\frac{ad}{bd}<\frac{ad+1}{bd}<\frac{bc}{bd}\]Otherwise multiply x and y by \(\frac{2}{2}\), and choose \[\frac{2ad+1}{2bd}\]
thaankkksss :DDDDDDDDDDDDDDDDD
@swissgirl u have a good sense of logic and reasoning;)
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