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Question: Estimate the limit: lim lnx/x-1 as x goes to 1
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do you know lhopitals rule?
we talked about it earlier this week in class but I didn't get a clear understanding.
this is LHopital's rule: \(\huge \lim_{x\rightarrow1} \frac{lnx}{x-1}=\lim_{x\rightarrow1} \frac{[lnx]'}{[x-1]'} \)
ok but when he explained this it made no sense
prolly because of the conditions needed in order to use the rule... to use this rule you have to determine if you have an indeterminate case: 0/0, inf/inf, 0^inf, etc.... this case is 0/0, so the rule applies...
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O ok
so taking the derivative of the top: 1/x derivative of the bottom: 1 so lim(as x approaches 1) lnx/(x-1) = lim(as approaches 1) 1/x/1 = 1
ok
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