Question: Estimate the limit:
lim lnx/x-1 as x goes to 1

Question

Question: Estimate the limit: 
lim lnx/x-1 as x goes to 1

anonymous · Answer

do you know lhopitals rule?

anonymous · Answer

we talked about it earlier this week in class but I didn't get a clear understanding.

anonymous · Answer

this is LHopital's rule:
$\huge \lim_{x\rightarrow1} \frac{lnx}{x-1}=\lim_{x\rightarrow1} \frac{[lnx]'}{[x-1]'} $

anonymous · Answer

ok but when he explained this it made no sense

anonymous · Answer

prolly because of the conditions needed in order to use the rule... to use this rule you have to determine if you have an indeterminate case:  0/0, inf/inf, 0^inf, etc....

this case is 0/0, so the rule applies...

anonymous · Answer

O ok

anonymous · Answer

so taking the derivative of the top: 1/x
derivative of the bottom: 1

so lim(as x approaches 1) lnx/(x-1) = lim(as approaches 1) 1/x/1 = 1

anonymous · Answer

ok