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Solve 5+8i-4+2i
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Simply add/subtract the real and imaginary parts separately and express in "a+ib" form!
so 1+10i?
^that's right
yeah correct-o!
wat about i7? 7 is an exponent
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you mean \(\iota^7\) right?
yea i guess
okay do you know that i^2 =-1, i^3=-i, i^4=1, i^5=i again, i^6=-i... and so on? what would i^7 be according to this trend?
-1?
here's a hint for you!! if the exponent is odd (except for 3) the answer is -i if the exponent is even (other than 2) the answer is 1
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ohk so its -i
yes -i!
ohk thnx!
anytime!
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