Question

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Answer 1

-9\[-9\sqrt32 + 9\sqrt18 + 10\sqrt8\]

Answer 2

factorizes the number inside the surd

Answer 3

@Candy05 Did you understand?

Answer 4

No I didn't.

Answer 5

\[-9\sqrt32 + 9\sqrt18 + 10\sqrt8\]
Is this your question?

Answer 6

Yes thats my question.

Answer 7

do you know how to solve for root(32) ??

Answer 8

okay whenever we have a number in root, the first step is to factor the term?
\[\sqrt{18}\]
Could you tell me the factors of 18?

Answer 9

9, 2

Answer 10

Good, so we have now
\[\sqrt{18}=\sqrt{9\times 2}\]
Now can you factor 9?

Answer 11

3,3

Answer 12

We get finally
\[\sqrt{18}=\sqrt{3\times 3\times 2}\]
As the 3 is appearing twice in the root, we can bring it out as one 3
\[\sqrt{18}=\sqrt{\underline{3\times 3}\times 2}=3\sqrt{2}\]
Do you get this?

Answer 13

Yes

Answer 14

Could you simplify \[\sqrt{32}\]?

Answer 15

4,2

Answer 16

What did you get?
\[\sqrt{4\times \times 4\times 2}=4\sqrt{2}\]??

Answer 17

8,4

Answer 18

You made a mistake
We have
\[\sqrt{32}=\sqrt{4\times 4\times 2}=4\sqrt{2}\]

Answer 19

Im getting confused

Answer 20

Which part you don't get?

Answer 21

Can you work the problem so I can see what i'm doing wrong?

Answer 22

Okay, I'll show you the simplification of \(\sqrt {32}\)
Let's factor it first
\[32=16\times 2\]
We can rewrite it as
\[32=4\times 4\times 2\]
so we have
\[\sqrt{32}=\sqrt{\underline{4\times 4}\times 2}\]
Notice that there are two 4s, we could get one out
\[\sqrt{\underline{4\times 4}\times 2}=4\sqrt{2}\]
Do you get this?

Answer 23

@Candy05 ??