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Integrate from sqrt(x) to 2 : sin(y^3) dy? how do i solve it? i tried u substitution, u= y^3, du = 3y^2, but then i dont kno what to do next
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is that the entire problem...or was it originally a double integral
DOUBLE INTERRAL
:) good...switch the limits of integration and then work out the problem
ILLL PUT THE CORRECT WAY, INGRATE(Y=0 TO y=2) ingrate(x=0 to x=y^2) sin(y^3) dxdy
Integrate wrt x first
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y take the to intreate (0 to 2) (y^2)sin(y^3)dy then?
yeah
now your substitution step will work
ohh :D
thanks
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no prob
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