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Give an algebraic proof that: 2n choose 2 = 2*(n choose 2) + n^2
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i think all you need is to write out what both sides actually are
on the other hand, being algebra challenged today, either it is wrong or i am missing something
that's right, just not sure about the expansion
lhs is \(2n(2n-1)=4n^2-2n\) rhs is \(2n(n-1)+n^2=2n^2-2n+n^2=3n^2-2n\) so either they are not the same or i a need to go get more coffee
you didn't divide by 2
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ho ho ho
guess that would help wouldn't it?
you do need to hit the coffee :)
yeah i am really messing up today i blame the heat which is in fact why i am indoors on a saturday
\(\binom{2n}{2}=\frac{2n(2n-1)}{2}=n(2n-1)\) \(2\binom{n}{2}+n^2=\frac{2n(n-1)}{2}+n^2\) now algebra
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