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Mathematics 15 Online
OpenStudy (anonymous):

.......

OpenStudy (anonymous):

OpenStudy (anonymous):

How many aces are there in 52 cards??

OpenStudy (anonymous):

i have no idea, i don't play cards sorry

OpenStudy (anonymous):

It is okay.. Then you must play them otherwise you can't solve this type of questions..

OpenStudy (anonymous):

thats a picture of a deck

OpenStudy (anonymous):

that's a differnet problem, but thank you

OpenStudy (anonymous):

So in 52 there are 4 aces.. So, Probability of choosing an ace : 4/52 As there is only one queen of hearts, so, And probability of choosing a heart queen: 1/51 \[P = \frac{4}{52} \times \frac{1}{51} = \frac{1}{663}\]

OpenStudy (anonymous):

i thought it would have been 1/2652 or something

OpenStudy (anonymous):

why is it not 1/52 x 1/51 ? the ace of spades is only one, right (?___?)

OpenStudy (anonymous):

Sorry I am wrong..

OpenStudy (anonymous):

\[P = \frac{1}{52} \times \frac{1}{51} = \frac{1}{2652}\]

OpenStudy (anonymous):

go to the website i told

OpenStudy (anonymous):

okay, i did

OpenStudy (anonymous):

so, is it 1/2652?

OpenStudy (anonymous):

yup

OpenStudy (anonymous):

thank you

OpenStudy (anonymous):

1/52 times 1/51= 1/2652 Thats the probability of getting both an ace of spades and a queen of hearts, but the probability of getting the queen of hearts after just taking one card out is 1/51 Also note 1/1326 is the probability of getting a queen of hearts and an ace of spades if order does not matter.

OpenStudy (anonymous):

@doubledrive , do i put 1/2652?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

thank you

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