Question

please help me to integrate ln(x^2 + 4)

Answer 1

log you integrate by parts
always the same trick put \(u=\ln(x^2+4), dv=1\)

Answer 2

ya i got that part, but itz later on dat i get stuck

Answer 3

i gotta run
maybe myininaya will help

Answer 4

\[\int\limits_{}^{}\ln(x^2+4)=x \ln(x^2+4)-\int\limits_{}^{}\frac{2x^2}{x^2+4}\]

Answer 5

oh ok, sure thnx

Answer 6

@NotSObright : i got stuck exactly there

Answer 7

Y\[\frac{2x^2}{x^2+4}=\frac{x^2+4+x^2+4-8}{x^2+4}=\frac{x^2+4}{x^2+4}+\frac{x^2+4}{x^2+4}-\frac{8}{x^2+4}\]

Answer 8

oops ignore that Y
that was accidental type in thingy

Answer 9

thank youuuuu so much everyone!!!!!!!!

Answer 10

Wow you got it so quickly?
Really you understand?

Answer 11

yep....i jst u knw sorta needed some help getting outta that 2x^2/(x^2+4)

Answer 12

cool
you could have used long division but i like the way i did it :)

Answer 13

When the degrees of the polys on top and bottom are the same do long division (or find shortcut like I did)
If the degree on top is larger do long division

Answer 14

thank you!!!!!!!!!!!!

Answer 15

Np. Peace
@satellite73 is awesome too! :)

Answer 16

uh...ya bt i cn make both ur answers best answers, so u knw....lol

Answer 17

I know. :(
Its all cool though.

Answer 18

:)