Mathematics
8 Online
OpenStudy (anonymous):
The distance between the points (1,8) and (4,4) is equal to 5.
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OpenStudy (anonymous):
True or false?
OpenStudy (helder_edwin):
do you know how to compute the distance between 2 points?
OpenStudy (anonymous):
no i dont. can u explain it to me?
OpenStudy (anonymous):
\[\sqrt{(\Delta x)^2+(\Delta y)^2}\]
OpenStudy (anonymous):
woahh
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OpenStudy (anonymous):
thanks
OpenStudy (anonymous):
k...do you know what to do from here?
OpenStudy (anonymous):
no, ive actually never seen that. im just going to try it
OpenStudy (anonymous):
so, change in x is 4-1=3
change in y is:4-8=-4
square them. add the result. take square root.
OpenStudy (anonymous):
thank you very much. i appreciate it
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OpenStudy (anonymous):
no prob; let me know what you get
OpenStudy (anonymous):
okay im doing it now
OpenStudy (anonymous):
i do the -4+3=-1?
OpenStudy (anonymous):
no. square each one individually first.
OpenStudy (anonymous):
\[3^2+(-4)^2\]
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OpenStudy (anonymous):
then take the square root of whatever you get
OpenStudy (anonymous):
9+-16=-7
OpenStudy (anonymous):
no
OpenStudy (anonymous):
no wait, i did it wrong because i cant square a neg. number
OpenStudy (anonymous):
9+16
because\[(-4)^2=(-4)(-4)=16\]the square of a negative is a positive number
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OpenStudy (anonymous):
oh sorry. i suck at math.
so i square the 16 and get 4?
OpenStudy (anonymous):
you square the -4. The gives you 16. the negative sign goes away.
OpenStudy (anonymous):
so now you should have:\[\sqrt{9+16}\]
OpenStudy (anonymous):
9+16=25
25=5
OpenStudy (anonymous):
well I assume you mean\[\sqrt{25}=5\]but yeah, there's your distance
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OpenStudy (anonymous):
Yes it´s 5.
OpenStudy (anonymous):
sqrt((x2-x1)^2+(y2-y1)^2)= sqrt ((4-1)^2+(4-8)^2
OpenStudy (anonymous):
sqrt((3)^2 +sqrt(-4)^2) = sqrt((9) +sqrt(16))= sqrt (25) = 5