What is the simplified form of ?
4x/x^2-4 divided by 8x^2/x^2+4x+4
\[\Large \frac{\frac{4x}{x^2 - 4}}{ \frac{8x^2}{x^2+ 4x + 4}}\]When you have to divide a fraction by another fraction we multiply the first fraction with the reciprocal of the second fraction\[\Large \frac{4x}{x^2 - 4} \times \frac{x^2+ 4x + 4}{8x^2}\]
4x^3+16x^2+16x/8x^4-32x^2
what?
i multiplied like you said
No.. don't multiply it now ,you can just cancel out few things and it'll be simplified :)
ohh okay lol my mistake
\[\Large \frac{\cancel{4x}}{x^2 - 4} \times \frac{x^2+ 4x + 4}{\cancel{8x^2}^{2x}}\]
oh so you just see what things can match kinda and then cancel
\[\Large \frac{1}{x^2 - 4} \times \frac{x^2+ 4x + 4}{2x}\]
Yes exactly :D
Now factorise x^2 + 4x + 4
that would be (x+2)^2
Yes factorise x^2-4 now :)
(x+2)(x-2)
so you could cancel out 1 of the (x+2)^2 on both sides. then get 1/x-2 * x+2/2x
x+2/2x(x-2) would be the answer ?
Yes :D Very Good :D @candygirl7655 *sorry got disconnected
thank you
Anytime :)
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