In circle A shown below, BD is a diameter and the measure of CB is 36°. What is the measure of ∡DBC? 36° 72° 18° 54°
@jim_thompson5910 can you look at this? I got the answer 54..
A is the center. So DAB is 180 degrees since "BD is a diameter" Therefore, arc DBC is 36+180 = 216 which leaves 360 - 216 = 144 for arc DC Are you seeing how I'm getting all this?
ohhhh okay. I did DCB=90 angle BDC=36 degrees so angle DBC=180-(angle BDC+ angle DCB)=180-(36+90)=54 degrees
ah, that's where you made a typo... angle BDC is NOT 36 degrees
the central angle BAC is 36 degrees, and using the inscribed angle theorem, BDC is what?
Ohhhh, I see what i did!!
that's great
so what is the final answer then?
36
close...but not quite
would it be 18?
no
You should have gotten that angle BDC is 18 degrees, so angle DBC=180-(angle BDC+ angle DCB)=180-(18+90)=72 degrees
Alright...thank you
you're welcome
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