In circle A shown below, BD is a diameter and the measure of CB is 36°. What is the measure of ∡DBC?
36°
72°
18°
54°
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OpenStudy (sarahc):
OpenStudy (sarahc):
@jim_thompson5910 can you look at this? I got the answer 54..
jimthompson5910 (jim_thompson5910):
A is the center. So DAB is 180 degrees since "BD is a diameter"
Therefore, arc DBC is 36+180 = 216
which leaves 360 - 216 = 144 for arc DC
Are you seeing how I'm getting all this?
OpenStudy (sarahc):
ohhhh okay. I did DCB=90
angle BDC=36 degrees
so angle DBC=180-(angle BDC+ angle DCB)=180-(36+90)=54 degrees
jimthompson5910 (jim_thompson5910):
ah, that's where you made a typo...
angle BDC is NOT 36 degrees
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jimthompson5910 (jim_thompson5910):
the central angle BAC is 36 degrees, and using the inscribed angle theorem, BDC is what?
OpenStudy (sarahc):
Ohhhh, I see what i did!!
jimthompson5910 (jim_thompson5910):
that's great
jimthompson5910 (jim_thompson5910):
so what is the final answer then?
OpenStudy (sarahc):
36
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jimthompson5910 (jim_thompson5910):
close...but not quite
OpenStudy (sarahc):
would it be 18?
jimthompson5910 (jim_thompson5910):
no
jimthompson5910 (jim_thompson5910):
You should have gotten that angle BDC is 18 degrees, so
angle DBC=180-(angle BDC+ angle DCB)=180-(18+90)=72 degrees
OpenStudy (sarahc):
Alright...thank you
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