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Mathematics 22 Online
OpenStudy (sarahc):

In circle A shown below, BD is a diameter and the measure of CB is 36°. What is the measure of ∡DBC? 36° 72° 18° 54°

OpenStudy (sarahc):

OpenStudy (sarahc):

@jim_thompson5910 can you look at this? I got the answer 54..

jimthompson5910 (jim_thompson5910):

A is the center. So DAB is 180 degrees since "BD is a diameter" Therefore, arc DBC is 36+180 = 216 which leaves 360 - 216 = 144 for arc DC Are you seeing how I'm getting all this?

OpenStudy (sarahc):

ohhhh okay. I did DCB=90 angle BDC=36 degrees so angle DBC=180-(angle BDC+ angle DCB)=180-(36+90)=54 degrees

jimthompson5910 (jim_thompson5910):

ah, that's where you made a typo... angle BDC is NOT 36 degrees

jimthompson5910 (jim_thompson5910):

the central angle BAC is 36 degrees, and using the inscribed angle theorem, BDC is what?

OpenStudy (sarahc):

Ohhhh, I see what i did!!

jimthompson5910 (jim_thompson5910):

that's great

jimthompson5910 (jim_thompson5910):

so what is the final answer then?

OpenStudy (sarahc):

36

jimthompson5910 (jim_thompson5910):

close...but not quite

OpenStudy (sarahc):

would it be 18?

jimthompson5910 (jim_thompson5910):

no

jimthompson5910 (jim_thompson5910):

You should have gotten that angle BDC is 18 degrees, so angle DBC=180-(angle BDC+ angle DCB)=180-(18+90)=72 degrees

OpenStudy (sarahc):

Alright...thank you

jimthompson5910 (jim_thompson5910):

you're welcome

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