Question

Help with dividing polynomials

Answer 1

I recieved an answer of 8y^-7z but obviously it was incorrect

Answer 2

the 40/5 =8 is easy. You got that right.
now do the x's
\[ \frac{x^{-2}}{{x^2}} = x^{-2-2} = x^{-4} \]
the FIRST RULE is exponent on the top minus the exponent on the bottom.
The exponent for x on the top is -2, the exponent for x in the bottom is 2
and -2- 2= -4
so the answer is \( x^{-4} \)
However, they want all exponents to be positive.

use the SECOND RULE: to change the exponent, flip the fraction:
\[ x^{-4}= \frac{x^{-4}}{1}= \frac{1}{x^4} \]

so we have so far:
\[ \frac{8}{x^4} \]
now do the y and z terms

Answer 3

ok so y=-7 and z= -1

Answer 4

for
\[ \frac{y^{-3}}{y^{-4}} \]
what is the exponent of y on the top?
and on the bottom?
now subtract top minus bottom

Answer 5

-3-(-4)
-3+4
y= -1

Answer 6

sorry

Answer 7

are you sure about -1? -3+4 is the same as 4-3

Answer 8

oh sorry 1

Answer 9

so the answer for the y's is
\[ y^1 \]
or simply y (no need to write the 1)
now do z's

Answer 10

0-(-2)
z=2

Answer 11

Be careful. the exponent of z will be +2
so the answer is ?

Answer 12

3

Answer 13

when you do 0-(-2)= 2
you found what the little number is that goes in the upper right of z

Answer 14

z^0 is 1
so its z^-2 at the bottom

Answer 15

the z are given as
\[ \frac{z^0}{z^{-2}} \]
we want to simplify to
\[ z^n \] where n is some number. How do we find n? top exponent minus bottom exponent.

Answer 16

1

Answer 17

you do 0- (-2)= 2 to find n. so the answer (for z) is
\[ z^2 \]

Answer 18

thats what I said before above

Answer 19

you said z=2
they would mark you wrong, because they want
\[ z^2 \]

Answer 20

so the final answer is
\[ \frac{8yz^2}{x^4} \]

Answer 21

Here is a video (and the ones after it), that might help you
http://www.khanacademy.org/math/arithmetic/basic-exponents/v/level-1-exponents

Answer 22

thank you for helping me...and for the video

Answer 23

If you don't run out of popcorn, this one is useful
http://www.khanacademy.org/math/arithmetic/basic-exponents/v/exponent-rules-part-1