Question

What is the solution to the equation log2 x + log2 4 = 3 ?

Answer 1

x = 2








x = 128








x = 32








x = 1/2

Answer 2

if you equation
\[ \LARGE \log^2x+\log^24=3 \]
or
\[ \LARGE \log_2x+\log_24=3 \]

Answer 3

it's the second @helder_edwin .

Answer is x = 2

Answer 4

the bottom one

Answer 5

how did you get tht?

Answer 6

OK do you want the work or the answer.
@Diogo gave you the answer

Answer 7

i want the work

Answer 8

OK you have
\[ \LARGE 3=\log_2x+\log_24=\log_2x+\log_22^2=\log_2x+2 \]
do u get it?

Answer 9

put everything in log10 form.

example:

log(x)/log(2) + 2 = 3

log(x) = log(2)

x = 2

Answer 10

ohh okay i got it ! you guys explain it better then my book

Answer 11

\[\log _{2}4 = \log _{2} 2^2 = 2\]

so the equation is

\[\log _{2} x + 2 = 3... or ... \log _{2 } x = 1\]

using the log law

\[\log _{a}b = c ........ a^{\log _{a} b} = a^c ... or.... b = a^c\]

then \[x = 2^1\]

or x = 2