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Solve logx + 5 36 = 2
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is the equation \[\log x + 536 = 2\]
my guess is it is \[\large \log_{x+5}(36)=2\]
yes
write in equivalent exponential form as \((x+5)^2=36\) and solve that one
raise each side as powers of (x +5) then 36 = (x + 5) ^2 and then solve the quadratic
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takes two steps \[(x+5)^2=36\] \[x+5=6\] \[x=1\]
thank you
actually you should get two solutions to \[(x+5)^2=36\] but you can ignore the negative solution because the base of a logarithmic function is never negative
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