Question

How can the cotangent of an angle in a right triangle be calculated?

Answer 1

good question!



to get the cotangent of that theta you solve for adjacent over hypotenuse

in this case the adjacent of theta is b and opposite is a

therefore

\[\cot \theta = \frac{b}{a}\]
do you get that?

Answer 2

No , Not Really , My Options For The Answers Are :

by dividing the hypotenuse by the adjacent side

by dividing the adjacent side by the opposite side

by dividing the adjacent side by the hypotenuse

by dividing the hypotenuse by the opposite side

Answer 3

i said something wrong in my post....

to get the cotangent of that theta you solve for adjacent over opposite*

lol sotty for that mistake

Answer 4

sorry*

Answer 5

Thank You !

Answer 6

for future references

\[\sin = \frac{opposite}{hypotenuse}\]
\[\cos = \frac{adjacent}{hypotenuse}\]
\[\tan = \frac{opposite}{hypotenuse}\]
\[\csc = \frac{hypotenuse}{opposite}\]
\[\sec = \frac{hypotenusE}{adjacent}\]
\[\cot = \frac{adjacent}{opposite}\]