Indicate the equation of the line meeting the given conditions. Please put the equation in standard form. Containing A(1, 3) and B(0, 2)
Please explain how you did it too...
Do you know the formula for finding the slope of the line?
\[y-y _{1}=m(x-x _{1})\] where m is the slope. Can you put in the given values and solve to find m?
(3 - 2) = m(1 - 0) m = 1 The standard form for the equation of a straight line is y = mx + b where b is the intercept on the y axis ( where x = 0). So in this case we know that b = 2. So our equation is y = x + 2
@natnatwebb Do you understand how the equation was found?
Not really, doesn't standard form have to be like y+x=whatever? Also, isn't the slope formula \[x_{2}-x _{1}/y_{2}-y _{1}\]
you have it upside down \[m=\frac{y_2-y_1}{x_2-x_1}\]
you are comparing the y value to the x value, like miles per gallon or price per ounce y's go up top, x's in the bottom
so thats m, so you put in that number for m, put the y and x numbers in for x1 and y1, multiply the numbers, the just manipulate the equation till you have y and x on one side and a whole number on the other?
lets go slow
first we need the slope. we do it in our heads and then compute from \((0,2)\) to \((1,3)\) x increases by 1 unit (from 0 to 1) and so does y (from 2 to 3) so the slope is 1 now lets do it by computing \[m=\frac{3-2}{1-0}=\frac{1}{1}=1\]
now that we have the slope, we need the \(y\) intercept, which is what you get when \(x=0\) from the point \((0,2)\) we know if \(x=0\) then \(y=2\) so the \(y\) intercept is 2
we then get the equation right away \[y=1\times x+2\] but don't write \(1\times x\) because you teacher will think you are daft, so just write \[y=x+2\]
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