Question

LGBADERIVATIVE:

\[\frac{d^2y}{dx^2} \frac{x^2}{1+2x}\]

Answer 1

looks complicated..

Answer 2

Dude, no one wants to do your homework

Answer 3

lol im checking it

Answer 4

\[y' = \frac{2x(1+2x) - 2x^2}{(1+2x)^2}\]
right?

Answer 5

isn't there missing an equal sign or something?

Answer 6

equal sign?

Answer 7

i meant what's the second derivative of that thingy above...i think i may have used wrong notations

Answer 8

this \[\frac{d^2y}{dx^2}=\frac{x^2}{1+2x}\]

or this

\[\frac{d^2}{dx^2}\left[ \frac{x^2}{1+2x}\right]\]

Answer 9

Umm this derivative isn't really hard, I'm confused why you need help?

Answer 10

y' is fine

Answer 11

second one

Answer 12

because if i did the first derivative right....it looks complicated

Answer 13

Not to be rude, just, you usually ask more advanced stuff than this :P

Answer 14

Dude, learn the quotient rule.

Answer 15

@nbouscal yep im trying to enhance my derivative and integral skills...im gonna need it

Answer 16

Say it with me, "bottom derivative of top minus top derivative of bottom all over bottom squared"

Answer 17

@nbouscal, the derivative chorus?

Answer 18

Yes, this is how we learn the calculus, forget about the mathematics behind it and just learn the chanting :)

Answer 19

-snickers- Very well then. :P

Answer 20

(Ho D(Hi)- Hi D(Ho))/(Ho Ho)

Answer 21

\[\frac{d}{dx}\left[\frac{f(x)}{g(x)}\right]=\frac{f'(x)g(x)-f(x)g'(x)}{[g(x)]^2}\];P

Answer 22

Forget \((x)\). Be Lagrangian:
\[\frac{f'}{g'}=\frac{f'g-fg'}{g^2}\]

Answer 23

\[y' = \frac{2x(1+2x) - 2x^2}{(1+2x)^2}\\
y' = \frac{2x^2+2x}{4x^2+4x+1}\\
y''=\frac{(4x^2+4x+1)(4x+2)-(2x^2+2x)(8x+4)}{(4x^2+4x+1)^2}
\]Now simplify.

Answer 24

is that the same as
\[\Large \frac{2(1+2x)^3 - [2x(1+2x) = 2x^2](1+2x)}{(1+2x)^4}?\]

if so..then i can finally get back to my advanced topics

Answer 25

that equal sign is a minus

Answer 26

first u need to find the first y' prime and the second y'' prime

Answer 27

use the quotant rule
2 times

Answer 28

so many ppl views your hw or work lol

Answer 29

i think i got a different answer,,

Answer 30

nope this isnt homework lol..this is practice

Answer 31

I don't really feel like computing it out to compare our answers, I'm sure you can simplify the expressions lol

Answer 32

lol i'll just assume they're the same

Answer 33

I was attracted by the fact lgba is attempting to make his own type of derivative. I'm awaiting a formal definition.

Answer 34

lol formal definition huh

Answer 35

I'm pretty sure they are not the same, just from glancing at yours. I think you made some missteps in deriving.

Answer 36

You post questions and you're like,
LGBADERIVATIVE

Answer 37

heh why not

Answer 38

"find the derivative" was so drab for me

Answer 39

confuse the reader perhaps

Answer 40

well regardless of whether i was right or wrong..i'll now go back to d.e. i think i learned all i can from derivatives

Answer 41

Interestingly, mine simplifies to: \(\dfrac{2}{(2 x+1)^3}\).

Unfortunately, yours simplifies to: \(\dfrac{(6 x (x+1)+2)}{(2 x+1)^3}\)

Simplifications performed by The Wolf (tm)

Answer 42

I see what you did there: The Wolf and The Panda.