Question

Plz help:)

Answer 1

How to find G.C.D. of \[x^3-x^2-4-6\]&\[ x^2-2x-3\]

Answer 2

@lgbasallote plz help:)

Answer 3

G.C.D.=??

Answer 4

factorise the quadratic

(x - 3)(x +1) = 0

then x = 3 , -1

use the factor theorem for the cubic

Answer 5

are you sure its x^3 - x^2 - 4 - 6

Answer 6

Yeah! @campbell_st

Answer 7

4x*

Answer 8

so its actually x^3 - x^2 - 10

Answer 9

sorry @campbell_st
it's\[x^3-x^2-4x-6\]lol

Answer 10

full form of G.C.D.

Answer 11

???

Answer 12

ok... using the factor theorem

P(3) = (3)^3 - (3)^2 - 4(3) - 6
= 27 - 9 - 12 - 6
P(3) = 0

therefore (x - 3) is a factor of x^3 - 3x^2 - 4x - 6

so the GCD = ( x - 3)

Answer 13

yes k! thanx:)

Answer 14

Wht is th full form of GCD

Answer 15

Greatest Common Divisor??

Answer 16

its \[x^3 - x^2 -4x - 6 = (x -3)(x^2 + 2x + 2)\]

and

\[x^2 - 2x -3 = (x -3)(x +1)\]

Answer 17

k thanx:)