Question

definite integral

Answer 1

show that

Answer 2

\[\int\limits^{\pi/2}_{0} \sqrt{1-\sin x)(1+sinx)dx}=1\]

Answer 3

\[(1-\sin x)(1+\sin x)=1-\sin^2 x=\cos^2 x\]

Answer 4

\[\huge (1-\sin)(1+sinx) = 1-\sin^2x = \cos^2x\]

Answer 5

so?

Answer 6

Take the integral of cos^2x..

Answer 7

isnt it cos x?

Answer 8

\[\int\limits_{0}^{\pi/2} \sqrt{\cos^2 x} dx = \int\limits_{0}^{\pi/2} \cos x dx =\]

Answer 9

Yes it is cosx..

Answer 10

bt that it =-1

Answer 11

\[\huge \int\limits_{}^{}cosx.dx = sinx + C\]

Answer 12

\[\huge \sin \frac{\pi}{2}-\sin 0=1\]

Answer 13

u mean