how to calculate kinetic energy of a projectile at the highest point of a projectile?
i think it is the way we did in ruchi's problem. KE = 1/2 m (ucos theta)^2 i've checked online....and this is what i got everywhere.
For a projectile problem, the total energy is equal to the kenitic energy 1/2 mvv plus the potential energy mgh. Initially the total energy is all kinetic energy ant the highest ponint the energy is all potential.os kenitic energy is 0.
@roy402a the KE at the highest point is not 0. since the velocity at that point is not 0. only the vertical component of velocity = 0. the horizontal component remains constant throughout the motion. so the projectile has KE all throughout its motion.
no rdx said its the change wats it?
i know he did. even i didn't understand what he meant. he told me to google it. i did and i only found the relation i posted above. there was nothing about change in KE.
thnx vaidehi
:) but i'd suggest u clear it out with Rdx as well.
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