Question

Part 1: Describe the graphs of the functions f(x) = 2x – 3 and g(x) = –2x – 3.

Part 2: Compare and contrast the domain and range of f(x) and g(x)

Answer 1

have you graphed the functions?

Answer 2

they are both lines in slope intercept form, y=mx+b
where m is your slope and b is your y-intercept.
do you know how to graph from here?

Answer 3

kind of sort of

Answer 4

both lines have b values of -3, which means we can start graphing by plotting a point at -3 on the y-axis.
from that point we count out our rise and run from the slope.
\[slope=\frac{rise}{run}\]
in f(x), m=2 which can be represented as
\[\frac{2}{1}\]
which means a positive rise of 2 and a run of 1.
so from -3 go up 2, over to right 1 and plot a point.
now draw a line through both points.

Answer 5

we do same for g(x), but the m=-2 in g(x) so we represent -2 as
\[\frac{-2}{1}\]
which is a rise of negative 2 and a run of 1.
So, from -3 go down 2 and over to the right 1 and plot a point.
draw a line through these points.

these graphs should look like an X

Answer 6

domain represents all possible x values that have corresponding y values in the function
range represents all possible y values that have corresponding x values in the function

Answer 7

compare and contrast seems really boring here. let me know if you want my take considering
\[D:x \epsilon R \]
x is an element of the real numbers
\[R:y\epsilon R\]
y is an element of the real numbers