[7.08] Find the quotient of . the quotient is in the attatchment.

x^2 + 3xy^2 + 5

x^2 + 3xy − 5

4x^3 y + 12x^2 y^3 − 5

x^2 + 3xy^2 − 5

Question

[7.08] Find the quotient of .  the quotient is in the attatchment.

 x^2 + 3xy^2 + 5 

 x^2 + 3xy − 5 

 4x^3 y + 12x^2 y^3 − 5 

 x^2 + 3xy^2 − 5

anonymous · Answer

attachment

anonymous · Answer

@mathslover

matheducatormcg · Answer

since the denominator is a monomial, you can just divide out the common numeric factor and then divide out variables by
$$\frac{x^a}{x^b}=x^{a-b}$$

matheducatormcg · Answer

your answer will have 3 terms just as the numerator

anonymous · Answer

?

matheducatormcg · Answer

each term across the top and the denominator have a common factor of 4.  each can be divided by 4.  do that first.  every term gets divided by 4.

anonymous · Answer

i dont get how to divide them like do i divide the exponets two or just the numbers 4, 12, and -20?

anonymous · Answer

exponets to

matheducatormcg · Answer

just the numbers
your first step will like this
$$\frac{x^3y+3xy^2-5xy}{xy}$$

anonymous · Answer

and then isn't my answer whats left on the numerator?

matheducatormcg · Answer

not quite.
we got to take care of exponents.

anonymous · Answer

ok

matheducatormcg · Answer

we can split it into 3 fractions to help visualize
$$\frac{x^3y}{xy}+\frac{3x^2y^3}{xy}-\frac{5xy}{xy}$$

matheducatormcg · Answer

the variables with no exponent have an exponent of 1

matheducatormcg · Answer

and don't forget that anything to the zero power is 1

anonymous · Answer

ok

anonymous · Answer

so "y" by its self is really "1y"

matheducatormcg · Answer

no
$$y=y^1$$
is what i meant

matheducatormcg · Answer

oh but y is equal to 1y
just realized I may be saying that what you said was wrong which it was not, but i was trying to make the point about the exponent.

matheducatormcg · Answer

$$\frac{x^a}{x^b}=x^{a-b}$$
can be applied to each fraction to reduce

matheducatormcg · Answer

how'd you end up?
did you get an answer?