Question

x^2-5x+6=0

Solve by completing the square

Answer 1

x^2-5x+6
x^2-3x-2x+6
x(x-3)-2(x-3)
(x-2)(x-3)

Answer 2

can you explain how you got the -3x and -2x in the second step?

Answer 3

yes

Answer 4

standard form\[ax^2 + bx + c\]

now i split b into y and z, so that

\[y + z = b\]
\[y \times z = ac\]
in this case, b is -5 and ac is 6

so i chose y = -3 and z = -2

-3 + -2 = -5
-3 * -2 = 6

Answer 5

with y and z satisfy these conditions, you will be able to factor nicely

Answer 6

hmm so i didnt really need to do the whole (b/2)^2 thing cuz it just factored from the start?

Answer 7

ohhhhhh wooops completing the squareee, the method i used is called factoring

Answer 8

lemme try the other way

Answer 9

ya but you got the right answer that way haha

Answer 10

i like your way better

Answer 11

x^2-5x+6
x^2-5x = -6
\[x^2 -5x + \frac{25}{4} = -6 + \frac{25}{4}\]
\[(x-\frac{5}{2})^2=\frac{1}{4}\]
\[x-\frac{5}{2}=+-1/2\]
x = 6/2 = 3
x = 4/2 = 2

Answer 12

okay i get it now thank you

Answer 13

you re welcome