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Chemistry 8 Online
OpenStudy (anonymous):

A sample of ZnS is nearly 90 % pure. What percentage of Zn does it contains

OpenStudy (joppei):

I am too lazy to go look for molacular weights but you have to determine the weight percentage of zink in ZnS which you do as following: (MolecularweightofZinc)/(Molecularweightof(Zns)∗100 Then you multiply this number with 0,9 (the 90% from the purity)

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