Question

whats (rad)3^2x+4=9^x-2

Answer 1

rad?

Answer 2

\[\huge \color{green}{\textbf{Welcome To Openstudy..}}\]

Answer 3

Can you type your equation in using the equation button?

Answer 4

\[\sqrt{3}^{2x+4}=9^{x-2}\]

Answer 5

9 = √3 ^ 4

Answer 6

i know for that last question i have to set the exponents equal to each other

Answer 7

yeaa

Answer 8

but the base has to be same

Answer 9

so whats x??

Answer 10

ohhh mmmkkk i get ya thank!!!!!!!!!!!

Answer 11

cool :)

Answer 12

ill figure out x thanks for the help!!

Answer 13

The trick here is to "write nine as the square root of three ... raised to a power".

Notice how I increase the power on each sqrt(3)... does this make sense, just from an exponents point of view?

\[\huge \sqrt{3}^1=\sqrt{3}\]
\[\huge \sqrt{3}^2=3\]
\[\huge \sqrt{3}^3=3\cdot\sqrt{3}\]
\[\huge \sqrt{3}^4=9\]

Answer 14

thanks!!