Question

Determine how many grams of each of the following solutes would be needed to make 2.10x10^2 mL of a 0.100 M solution.
(A) Cesium Iodide (CsI)
(B) Sulfuric Acid (H2SO4)
(C) Sodium Carbonate (Na2CO3)
(D) Potassium Dichromate (K2Cr2O7)
(E) Potassium permanganate (KMnO4)


(D)

Answer 1

every solution from A to E has the same mols
n=MV=0.1*2.1*10^2*10^(-3)=0.021 mol

Answer 2

but how many grams of each of the solutes would be needed
u just need to find equivalent grams for 0.021 mol
for example (B) Sulfuric Acid (H2SO4)
grams=moles*Molecular weight=0.021*98=2.058 grams

Answer 3

Thank you so much for the help!! I have alot more questions if you are on and have time could please help!