Question

please help.
Simplify the rational expression. State any excluded values.
x^3-36/42 x-7x^2

Answer 1

\[\frac{x^3-36}{42x-7x^2}\] ?

Answer 2

thats the problem there wasn't meant to be a space between 42 and x

Answer 3

i am going to make a bet that it is
\[\frac{x^2-36}{42x-7x^2}=\frac{(x-6)(x+6)}{7x(6-x)}\]\]
if the numerator is in fact \(x^3-36\) there is not much you can do

Answer 4

if it is the second one i wrote you can factor and cancel since \(\frac{x-6}{6-x}=-1\)