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Mathematics 8 Online
OpenStudy (anonymous):

Help WITH crazy math problem

OpenStudy (anonymous):

OpenStudy (anonymous):

^^^

OpenStudy (anonymous):

I dont think you can solve for it manually because this is parabolas

OpenStudy (anonymous):

No. You can, I was forced to learn this for conics in my Pre-Calc class.

OpenStudy (anonymous):

oh ok I hate this stuff

OpenStudy (anonymous):

I don't understand what is it asking for though. Is it asking for a set of points or an equation?

OpenStudy (anonymous):

a set of points

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

Sorry if I take awhile. It's been almost a year since I've had to do this lol.

OpenStudy (anonymous):

Its okay

OpenStudy (anonymous):

ok that was wrong start with \(y=1+4x\) and replace in first equation then solve \[1+4x=x^2+4\]

OpenStudy (anonymous):

@satellite73 we did that together already.

OpenStudy (anonymous):

I was looking for the next step in my old notes.

OpenStudy (anonymous):

I am too

OpenStudy (anonymous):

Okay so if you do that you'll factor it out to get the zeros which is (x-1)(x-3) which will look like: |dw:1341781736502:dw|

OpenStudy (anonymous):

Sorry about it being so sloppy. I suck at drawing on here. But the points on the x access will be (1,0) and (3,0)

OpenStudy (anonymous):

It should look like that ^^^^^

OpenStudy (anonymous):

okay

OpenStudy (kinggeorge):

So that gives you the \(x\)-values. Just plug those into \(y=x^2+4\) and \(y-4x=1\) to get the \(y\)-values.

OpenStudy (anonymous):

Thank you for helping us. :D I was looking for that

OpenStudy (kinggeorge):

You're welcome.

OpenStudy (anonymous):

Thanks to the both of you, with your help I found the answer I needed

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