What is the simplified form of the expression the square root of the quantity 4 times c to the sixteenth power. − the square root of c squared. + 6the square root of c squared. + the square root of the quantity 9 times c squared.?

A:2c4 + 8c
B:2c4 + 10c
C:2c8 + 8c
D:2c8 + 10c

Question

What is the simplified form of the expression the square root of the quantity 4 times c to the sixteenth power. − the square root of c squared. + 6the square root of c squared. + the square root of the quantity 9 times c squared.?
 	
	A:2c4 + 8c
	B:2c4 + 10c
	C:2c8 + 8c
	D:2c8 + 10c

campbell_st · Answer

$$\sqrt{4c^{16}} - \sqrt{c^2} + 6\sqrt{c^2} + \sqrt{9c^2}$$

can you simplify any part of this question...?

anonymous · Answer

you can change the square root of 4c^16 to 2c^4 ?

campbell_st · Answer

you can... but there is more to do

anonymous · Answer

then the the square root of 9 is 3 but i dont know what the exponent would be

campbell_st · Answer

well all you need to solve is 

$$\sqrt{c^2} = ?$$

campbell_st · Answer

do you know about index laws...?

$$(c^{16})^{\frac{1}{2}}$$

campbell_st · Answer

as $$\sqrt{4c^{16}} ... does..\not.. = 2c^4$$

its just the power of c that is incorrect.

campbell_st · Answer

so you have 

$$2c^4 - \sqrt{c^2} + 6\sqrt{c^2} + 3\sqrt{c^2}$$

anonymous · Answer

Do i combine like terms ?

campbell_st · Answer

yes you can... but you need to simplify the square root of c^2

campbell_st · Answer

here is a something you need to know

$$\sqrt{c^2} = c......... \sqrt{4c^{16}} = 2c^8$$

anonymous · Answer

what was the answer for this question?