in(1-3x)+3=9
(1-3x)+3=9 its like this ?
yes and you have to use that log thing natural log
oh ok.. \(ln(1-3x) + 3 = 9\) like this right ?
yes :D correct can you explain how to do it as well
\(\ln(1-3x) + 3 = 9\) \(\ln(1-3x) = 6\)
we must know below thing, to proceed further : \(\huge \ln x = a \\ \huge=> x = e^a\)
you familiar with above formula ?
no
Ok.. can you pls tell what you know about logs ?
so that we can see how to go about the solution.. but there is only one way to solve this problem using above mentioned formula :\
i was using a plug in formula for it but the answers i got didnt match and not much :/ i watched a few youtube tutorials on them but nothing helped me further my understanding towards this
Okay. lets use the formula and move ahead. il explain the formula in the end ok
okay than thank you very much appreciate this
\(\ln(1-3x) = 6\) \(1-3x = e^6\) \(3x = 1-e^6\) \(x = \frac{1-e^6}{3}\)
is that the answer or ur textbook converted it into numberical
i think it is converted
whats the answer ?
http://www.google.co.in/search?aq=f&sugexp=chrome,mod=13&sourceid=chrome&ie=UTF-8&q=(1-e%5E6)%2F3 is this ?
yes it was :)
but im a little lost on the last part can you explain it
great :)
ok
what point u stuck at
\(\ln(1-3x) = 6\) \(1-3x = e^6\) here ?
yes
sorry my computers actin slow i have 2 keep refreshing it
np :)
thank u for understanding and helping
\(\ln(1-3x) = 6\) can also be written as : \(\log_e(1-3x) = 6\) now we apply the formula : \(log_a x = c => x = a^c\)
mmhmm
i understand u... but im failing to explain eloquently lol
its fine i get it somewhat ill be back with another qustion though
Ok.. may be someone else can pitch in and help u understand @phi
@mahmit2012
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