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Mathematics 18 Online
OpenStudy (anonymous):

when the number 3^100 is divided by 5, what is the value of the remainder?

OpenStudy (anonymous):

3^1 divided by 5 -> reminder is 3 3^2 divided by 5 -> reminder is 4 3^3 divided by 5 -> reminder is 2 3^4 divided by 5 -> reminder is 1 3^5 divided by 5 -> reminder is 3 3^6 divided by 5 -> reminder is 4 3^7 divided by 5 -> reminder is 2 .... see the regularity? Every 4 numbers, it repeats. it's a set. SO, 100/4 is 25, an , which means the set repeated 25 times, and ended with the last one on the set. So the reminder is 1

OpenStudy (anonymous):

oh wow thanks!

OpenStudy (anonymous):

but im still a little confused about why 100/4

OpenStudy (kinggeorge):

If you're familiar with Fermat's Little Theorem: Since \(100\equiv0\pmod4\) you know that \[3^{100}\equiv(3^4)^{25}\equiv1^{25}\equiv1\pmod5\]So the remainder is 1.

OpenStudy (anonymous):

thank you so much!! :D

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