Find the slope of the line through the pair of points. A(2, –3), P(2, 9)
the slope of a line through two given points \(\large (x_1,y_1) \) and \(\large (x_2,y_2) \) is the formula: \(\large slope=m=\frac{y_2-y_1}{x_2-x_1} \)
okay they give me these choices A. 0 B. 2/3 C. - 1/3 D. undefined
let's calculate the values... \(\large y_2-y_1= \) and \(\large x_2-x_1= \)
ok i just started these so i honestly dont even know
\(\large y_2-y_1= \) means subtract the y-coordinates...
so 1?
\(\large x_2-x_1= \) means subtract the x-coordinates
so it's - 1/3
\(\large (x_1,y_1)=(2, -3) \) \(\large (x_2,y_2)=(2, 9) \)
okay so what i am understanding from what you just wrote out is it is undefined
\(\large (y_2-y_1)=9-(-3)= \)
...
i'm trying to make you figure this out if you'd only answer my questions...
9 - (-3) = 6?
no... 9-(-3)=12
oh it goes up? ok that was a help next
\(\large (x_2-x_1)= \) ???
2 -9 ? 7
what are the x-coordinates the the two points?
it says A(2, –3), P(2, 9)
so \(\large x_1=2 \) and \(\large x_2=2 \) so what's \(\large x_2-x_1= \) ???
\(\large x_2-x_1=2-2=0 \) so \(\large slope=m=\frac{y_2-y_1}{x_2-x_1}=\frac{9-(-3)}{2-2}=\frac{12}{0}=???? \)
12
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