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Mathematics 7 Online
OpenStudy (anonymous):

Please Help ......

OpenStudy (anonymous):

OpenStudy (anonymous):

@dumbcow @radar will probably help

OpenStudy (anonymous):

@dumbcow, @jim_thompson5910, @zepp , @myininaya or anyone? please

OpenStudy (anonymous):

@Eyad would you help me?

jimthompson5910 (jim_thompson5910):

a) should be the other way around, so Kendra is correct It should be RW = 2/3*RU This is because the medians meet at a point which cuts each median into two parts that are 2:1 in ratio (ie one part is double the other)

OpenStudy (anonymous):

1a) In this triangle, the 3 perpendicular bisectors cross themselves @ the point W. So, you can write that : (1) : UW = (1/3)RU (2) : VW = (1/3)VS (3) : TW = (1/3)TQ You can see that : RW = RU - UW, but according to the equation (1) : UW = RU/3 RW = RU - (1/3)RU RW = (3/3)RU - (1/3)RU RW = [(3 - 1)/3]RU RW = (2/3)RU (2/3)RW = (2/3)(2/3)RU (2/3)RW = (4/9)RU So we can say that the Jordan's comment is wrong. Kendra disagrees. I'm not agree with Jordan. 1b) You can see that : QW = QT - TW, but according to the equation (3) : TW = (1/3)TQ QW = QT - (1/3)TQ QW = (3/3)QT - (1/3)TQ QW = (3/3)QT - (1/3)QT QW = [(3 - 1)/3]QT QW = [2/3]QT [2/3]QT = QW QT = (3/2)QW, if QW = 27 inches QT = (3/2) * 27 QT = 81/2 (inches)

OpenStudy (anonymous):

Woah.. @thank YOu

OpenStudy (anonymous):

Yw @Trexy :D

OpenStudy (anonymous):

thanks @Eyad and @jim_thompson5910

jimthompson5910 (jim_thompson5910):

yw

OpenStudy (anonymous):

so Kendra is Correct right?

jimthompson5910 (jim_thompson5910):

yes

OpenStudy (anonymous):

Part B is 81/2 or 40.5

jimthompson5910 (jim_thompson5910):

that's correct

jimthompson5910 (jim_thompson5910):

you can verify by taking 2/3 of QT = 40.5 to get QW = 27

OpenStudy (anonymous):

because its asking for Round to the nearest tenth if necessary. so for the part B it will be 40.5?

jimthompson5910 (jim_thompson5910):

yes

OpenStudy (anonymous):

thank you

jimthompson5910 (jim_thompson5910):

sure thing

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