Question

How do i solve this?? x+11/x+3 multiplied by x^2-9/x^2+20x+99

Answer 1

it the same as the problem you wrote before
you have to factor the second fraction

Answer 2

how do you factor x^-9 and x^2+20x + 99?

Answer 3

yeah

Answer 4

yeah isn't how you answer :c
try factor them~

Answer 5

come on!
you have to learn this!
look at the previous excercise @nphuongsun93 did 4 u!
how do you factor
\[ \Large x^2-9=(x\qquad)(x\qquad) \]
?

Answer 6

would it be x-3 and x +3

Answer 7

yes!

Answer 8

now factor
\[ \Large x^2+20x+99=(x+\qquad)(x+\qquad) \]

Answer 9

okay.give me a sec to work it out:)

Answer 10

remember!
you are looking for two numbers such that multiplied =99 and added =20

Answer 11

okay so i got. (x+9) and (x+11)

Answer 12

\[x^2+20x+99\]
\[x^2+11x+9x+99\]
\[x(x+11)+9(x+11)\]
\[(x+9)(x+11)\]

Answer 13

good work!

Answer 14

Ok now YOU have
\[ \Large \frac{x+11}{x+3}\cdot\frac{x^2-9}{x^2+20x+99}= \]
\[ \Large \frac{x+11}{x+3}\cdot\frac{(x-3)(x+3)}{(x+9)(x+11)} \]
what do you get?

Answer 15

x-3 and x+9 ?

Answer 16

and?

Answer 17

you are working on fractions!

Answer 18

x-3/ x+9 is that how i should write it ?

Answer 19

yes!
\[ \Large \frac{x-3}{x+9} \]

Answer 20

okay!:) thanks for helping!

Answer 21

you are welcome